disgusting c1 question, could u help please? Watch

alevelshmaylevel92
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(2+?2)(3+?5)(?5-2)
(?5 -1)(1+?2)




yh, this q is very "not nice" could u help me n tell me step by step if you could? thank you xx

oh dear the question marks r supposed to be square root signs, darn tsr glitch,
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Mr M
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You will never get a real C1 question like this as it tests the same skill repeatedly.

What have you done so far?

Have you expanded the numerator or denominator?
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Manitude
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Exactly what are we supposed to do with that? Simplify it? Solve it assuming it equals zero? Rationalise?
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nuodai
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I'd recommend starting by expanding the numerator and denominator and putting them both in the form a+b\sqrt{c}, and then doing what you'd do if you saw any other fraction in that form.

(Original post by Manitude)
Exactly what are we supposed to do with that? Simplify it? Solve it assuming it equals zero? Rationalise?
I hope you don't make a habit of setting non-zero constants equal to zero :p: As for the other two options, given that this is a C1 question, 'simplify' and 'rationalise' will probably mean the same thing and be what's supposed to be done. Just guessing.
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soutioirsim
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\sqrt2
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Manitude
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(Original post by nuodai)
I'd recommend starting by expanding the numerator and denominator and putting them both in the form a+b\sqrt{c}, and then doing what you'd do if you saw any other fraction in that form.



I hope you don't make a habit of setting non-zero constants equal to zero :p: As for the other two options, given that this is a C1 question, 'simplify' and 'rationalise' will probably mean the same thing and be what's supposed to be done. Just guessing.
I do physics, therefore constants of integration are almost always set to zero without actually proving it
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nuodai
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(Original post by Manitude)
I do physics, therefore constants of integration are almost always set to zero without actually proving it
But then you're setting a zero constant equal to zero, so that's fine :p:
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Cermo
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The answer is 4.
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Manitude
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(Original post by nuodai)
But then you're setting a zero constant equal to zero, so that's fine :p:
Yes, most of the time they are equal to zero - or the law/formula you're trying to derive simply falls apart.

But we never talk about how or why they might equal other values than zero and what that would represent physically. That kind of annoys me.
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A level Az
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I see ya driving round town with the girl I love and I'm like forget youuuuooo-oooo...

NEG?! People don't appreciate good music nowadays...
Last edited by A level Az; 7 years ago
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Artemis 97
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(Original post by alevelshmaylevel92)
(2+?2)(3+?5)(?5-2)
(?5 -1)(1+?2)


(2+root2)(3root5 - 2root5 + 5 - 6)
-------------------------------------------
(root5 -1)(1+root2)


= (2+root2)(root5 - 1)
-------------------------
(root5 -1)(1+root2)

= 2 + root2
--------------
1 + root2

= (2+root2)(1 - root2)
--------------------------
(1+root2)(1 - root2)

= 2 - 2root2 + root2 - 2
-----------------------------
1 - root2 + root2 - 2

= -root2
--------
-1

= root2




very sorry, my keyboard is broken so i can only use half the keys, this is much easier to see if you write it out with the proper square root signs.
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tafadar
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done it on paper makes it easier to see.
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alevelshmaylevel92
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(Original post by tafadar)
done it on paper makes it easier to see.
Ok dude, you rock my pretty pink socks!!!!!!!!!!!!!!! THANK YOU for taking the time to write it out on paper, take a pic and put it up here, TSR is full of brilliant people thank u babe xx
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tafadar
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ur welcome
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