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# Core 3 question watch

1. Sorry guys for asking another question i am just really stuck again FML
Could anyone show me how to do this question

y=f(x) and y=g(x) only intersect at the point A, whose x-coordinate is alpha show that alpha satisfies the equation x= 3 + 1/x + 1/x^2

where f(x)=(x+1)/(x-1) and g(x)=Root x (or x^1/2 if you like it in faction form better)

Many thanks in advance
2. (Original post by Sheldon)
Sorry guys for asking another question i am just really stuck again FML
Could anyone show me how to do this question

y=f(x) and y=g(x) only intersect at the point A, whose x-coordinate is alpha show that alpha satisfies the equation x= 3 + 1/x + 1/x^2

where f(x)=(x+1)/(x-1) and g(x)=Root x (or x^1/2 if you like it in faction form better)

Many thanks in advance
Where the two graphs intersect you will have f(x) = g(x), and alpha will satisfy this equation.

So, set your equation up. The first thing you need to do is get rid of the square root, as it's not in your desired equation; so square everything, multiply through by the denominator, and see what you can do from there.

Post working if you're still stuck.
3. (Original post by Sheldon)
Sorry guys for asking another question i am just really stuck again FML
Could anyone show me how to do this question

y=f(x) and y=g(x) only intersect at the point A, whose x-coordinate is alpha show that alpha satisfies the equation x= 3 + 1/x + 1/x^2

where f(x)=(x+1)/(x-1) and g(x)=Root x (or x^1/2 if you like it in faction form better)

Many thanks in advance
Whenever a question says 'intersect', you should know that you have to put the equations of f(x) and g(x) equal to each other. You also need to get rid of the root x, since it isn't a nice thing to have in an equation. Post your working here if you have any further problems, and we'll help you further from there.

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