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    ok so i did this experiment- mixed together 7cm3 propanoic acid, 7cm3 ethanol, and 2cm3 sulfuric acid...and then let it reach equilibrium.

    i then added all that to distilled water till it was exactly 250cm3

    i used 25cm3 of this and titrated it with 0.1 NaOH
    the titration value was 34.6

    how would i work out the number of H+ ions in 25cm3 of acid?
    and how would i work out the number of H+ ions in 250cm3 solution?

    any help would be much appreciated
    thank you
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    You have a fixed volume and fixed concentration of base. So you can find the number of moles of hydroxide you've added

    That number will be the same as the number of moles of protons in your 25cm flask, and the number in 250cm3 will be 10 times that ammount!

    Easy peasy. Just remember c=n/v
 
 
 
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