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    Hi there!!

    I don't understand part b in problem 3 in section 1E.

    Can someone please explain? It just nags me that i don't get it!!

    Thankx!!!
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    ...? What's the question?
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    Hi , how are you? Stephen

    I have posted the question in two scans. Part b , the expecation part is what I don't get? If you could explain the reasoning in detail.

    thanx

    dave
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    Let the no. of defectives is X~B(10, 0.01).

    if X=1 then you're going to end up sampling 20 items,
    if X is not equal to 1 then you just need the initial sample of 10 items (to decide whether to accept/reject the batch).

    So Expected number of items sampled = 20*P(X=1) + 10*[1 - P(X=1)]
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    Big Thanx to benevolent member!!!
 
 
 
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