Hey there! Sign in to join this conversationNew here? Join for free

Electronics - Relaxation Oscillator (Schmitt Trigger) watch

    • Thread Starter

    My circuit uses a 4011 Schmitt trigger NOT gate, a capacitor and two resistors, acting as a relaxation oscillator. I know that as standard the Schmitt Trigger has a lower trip point of 2.2V and a 2.8V upper trip point with a +5V input.

    My question is what happens when I change the input voltage to +10V or +15V? How would I work out the difference? I have the output trace for the circuit on each of those voltages, how would I find out using that?

    Thanks in advance,


    P.S. Sorry if I put this in the wrong place, but I couldn't see an electronics AS section.
Do you agree with the PM's proposal to cut tuition fees for some courses?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.