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Electronics - Relaxation Oscillator (Schmitt Trigger) watch

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    My circuit uses a 4011 Schmitt trigger NOT gate, a capacitor and two resistors, acting as a relaxation oscillator. I know that as standard the Schmitt Trigger has a lower trip point of 2.2V and a 2.8V upper trip point with a +5V input.

    My question is what happens when I change the input voltage to +10V or +15V? How would I work out the difference? I have the output trace for the circuit on each of those voltages, how would I find out using that?

    Thanks in advance,

    Digichris.

    P.S. Sorry if I put this in the wrong place, but I couldn't see an electronics AS section.
 
 
 
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