I am stuck and would appreciate some help!
1) f(x)= sin1/2x + cos1/3x
write down another value of X (not 0) for which f(x)=f(0) and f'(x)=f'(0)
So I got sin1/2x + cos1/3x =1
then I have no idea what to do LOL!
I also got 1/2cos1/2x- 1/3sin1/3x =1/2
Again I have no idea how to simplifiy or anything...
Help would be appreciated and plus rep given.
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- Thread Starter
- 07-04-2011 01:28
- 07-04-2011 02:13
Consider sin1/2x + cos1/3x =1.
If x=even multiple of pi, then the sine term vanishes.
So which values of x=2pi, 4pi, 6pi,...etc give cos(x/3)=1 ?
Clearly x=6pi, 12pi, 18pi,...etc will work.
Similarly for 1/2cos1/2x- 1/3sin1/3x =1/2, the sine term vanishes for x=multiples of 3pi = 3pi, 6pi, 9pi, 12pi,...etc
So which of these values give cos(x/2)=1 ?
Which solution is common to both equations?Last edited by vc94; 07-04-2011 at 03:25.