# The Earth takes one year to orbit the Sun at a distance of 1.5 x 10^11 m. Calculate i

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The Earth takes one year to orbit the Sun at a distance of 1.5 x 10^11 m. Calculate its speed.

Why is the answer in the book 29.9 kms-1?

*Speed = distance/time*

(1.5 x 10^8)/ (365*24*60*60) = 4.75646... kms-1

(1.5 x 10^8)/ (365*24*60*60) = 4.75646... kms-1

Why is the answer in the book 29.9 kms-1?

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#2

Because your title has to the power 11 and your working has to the power 8, maybe?

Either work in metres or km.

Either work in metres or km.

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#3

distance is wrong. you've used the radius not circumference.

basically you've calculated what the average speed of the earth would be if it took a year to crash directley into the sun

basically you've calculated what the average speed of the earth would be if it took a year to crash directley into the sun

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(Original post by

Because your title has to the power 11 and your working has to the power 8, maybe?

Either work in metres or km.

**DumpOrStay?**)Because your title has to the power 11 and your working has to the power 8, maybe?

Either work in metres or km.

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(Original post by

distance is wrong. you've used the radius not circumference.

basically you've calculated what the average speed of the earth would be if it took a year to crash directley into the sun

**didgeridoo12uk**)distance is wrong. you've used the radius not circumference.

basically you've calculated what the average speed of the earth would be if it took a year to crash directley into the sun

So the distance given is the radius? So the correct sum would be

(2 x pi x 1.5x10^8) / (365*24*60*60)

= 29.8857...

Yay

Thanks

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#8

The motion is circular, so you must find the circumference of the orbit first.

Pi x diamter = 3.14 x (2x1.5x10^8)=9.24x10^8.

Then use speed = distance/time

Speed = 9.24x10^8) / (365x24x60x60)=29.885 kms^-1

Pi x diamter = 3.14 x (2x1.5x10^8)=9.24x10^8.

Then use speed = distance/time

Speed = 9.24x10^8) / (365x24x60x60)=29.885 kms^-1

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