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# C4 Help watch

1. Solve the equation...

3sin x - cos 2x = 1 for 0 < x < 360

I turned that into sin^2x + 3sin x - 1...then what?
2. I'm presuming you mean sin^2 (x) as in sin(squared) x.

Either factorise it or simply use the quadratic formula, (-b+-rt(b^2 -4ac)) /2a
3. Uh, I think you may have got your identities a little mixed up. You should recall that:

.
4. (Original post by olipal)
Uh, I think you may have got your identities a little mixed up. You should recall that:

.
ops sorry I made a typo...

It should be...

2sin(squared)x + 3sin x - 1

so the values when factorised are (-0.5) & (-1)...

Then what do i do?
5. Never mind I got it, it was simple enough!

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