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    If a balance accurate to two decimal places was used to record the mass of ethanol
    collected, what would be the percentage error due to the balance readings if the total
    mass of ethanol collected was 20.10 g?

    Why is it (2 * 0.005)/20.1 * 100 NOT (0.005/20.1)*100
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    (Original post by jsmith6131)
    If a balance accurate to two decimal places was used to record the mass of ethanol
    collected, what would be the percentage error due to the balance readings if the total
    mass of ethanol collected was 20.10 g?

    Why is it (2 * 0.005)/20.1 * 100 NOT (0.005/20.1)*100
    They are assuming that you take two readings and that the difference is the mass of ethanol.
 
 
 
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