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    The question is basically about

    Ca(s)+H20(l) --> Ca(OH)2(aq)+H2(g)

    There are two question I am pretty confused about:




    c)The student repeated the experiment using the same mass of pure barium.

    The Student found that a smaller volume of hydrogen gas was produced, measured at RTP.

    (i) Explain why. [1]

    (ii) Suggest one other difference the student would observe between the reactions of water with calcium and of water with barium. [1]




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    Instead of telling you the answer maybe i can guide you :P

    You can see from the equation that you are producing hydroxides...

    What do you know about the solubilities of the hydroxides down group 2? <---- That should be a big enough hint

    In terms of the observations... once again think about the solubilities...
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    (Original post by YingYang)
    The question is basically about

    Ca(s)+H20(l) --> Ca(OH)2(aq)+H2(g)

    There are two question I am pretty confused about:




    c)The student repeated the experiment using the same mass of pure barium.

    The Student found that a smaller volume of hydrogen gas was produced, measured at RTP.

    (i) Explain why. [1]
    From the equation the moles of hydrogen are proportional to the moles of metal used...
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    If you're being really picky the state symbol for Calcium Hydroxide should be (s+aq)
    Barium Hydroxide is also the same.
    In terms of what the observable difference would be, this youtube video is your question in action:
    http://www.youtube.com/watch?v=hiBVj...eature=related
 
 
 
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