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    (Original post by nereik6794)
    There were 2 but I can't remember what I put either haha. I think it was correct though
    i can r ember there where to alkenes next to each other and one was an ez other wasn't because it didn't have two groups attached to c double bound c never mind i prob got it wrong
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    (Original post by thefirstnotlastsamurai)
    Yeah there was one actually.

    2NO + O2 ------> 2NO2 or something like that?
    i put: (wasn't entirely sure)

    NO + 02 -> NO2. + O (in that it formed another radical? like in the mechanism?)
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    (Original post by kimmey)
    for the one where u had to draw 2-methyl-propan-2-ol would u get the marks if u drew a DISPLAYED formula ? cus on most mark schemes they seem to have skeletal ?????
    you would get the marks because i drew displayed formula
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    ^H= 66 question?

    what number did ppl put for it, (lol i just put 66)
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    (Original post by potentialmedicalstudent)
    ^H= 66 question?

    what number did ppl put for it, (lol i just put 66)
    33 but I have no idea if that's correct lol
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    (Original post by potentialmedicalstudent)
    ^H= 66 question?

    what number did ppl put for it, (lol i just put 66)
    so did i but people on here say half the number
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    (Original post by king1234)
    you would get the marks because i drew displayed formula
    What I did was for the H2 draw the H's coming off. For the HBr I drew the H at one place and Br at the other and then swapped them for the 3rd drawing. Does this get the marks? With the double bond broken of course
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    (Original post by Tasha001)
    yeah it was 46. i spent ages trying to find how it would be 47 :confused:
    47 was there because of the isotope carbon-13 in some of the molecules, so there's a small peak to the right of the molecular ion due to that isotope in some of the molecules.
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    (Original post by nereik6794)
    What I did was for the H2 draw the H's coming off. For the HBr I drew the H at one place and Br at the other and then swapped them for the 3rd drawing. Does this get the marks? With the double bond broken of course
    erm 50/50 you might depends on the examiner tbh
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    (Original post by nereik6794)
    33 but I have no idea if that's correct lol
    it was 33, i think the reason that they asked the question is to make sure people understood that the enthalpy change in formation is the enthalphy change when ONE mole of a compound is made, there was 2 Moles of it whe it was 66, so it must've been 33 for one mole!
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    (Original post by l.a.s)
    it was 33, i think the reason that they asked the question is to make sure people understood that the enthalpy change in formation is the enthalphy change when ONE mole of a compound is made, there was 2 Moles of it whe it was 66, so it must've been 33 for one mole!
    Yeh I doubled it at first then I was thinking "lol wtf". So then I crossed my answer and wrote 33
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    is anyone going to post an unoficcial markshcheme
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    (Original post by king1234)
    erm 50/50 you might depends on the examiner tbh
    Let's hope he/she isn't a complete ***** then
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    for the hydrolysis one, does polarity decrease down the group?
    and for the why is it exothermic one, is it because it requires more energy to break the bond than forming them resulting in a negative delta H value?
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    (Original post by bagelbe)
    for the hydrolysis one, does polarity decrease down the group?
    and for the why is it exothermic one, is it because it requires more energy to break the bond than forming them resulting in a negative delta H value?
    Weaker bond enthalpy down the group. Less energy to break the bonds than the energy released forming the new bonds.
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    (Original post by nereik6794)
    Weaker bond enthalpy down the group. Less energy to break the bonds than the energy released forming the new bonds.
    Do you think I'll get a mark for writing that hydrolysis with Cl occurs faster as polarity decreases down the group?
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    (Original post by nereik6794)
    Let's hope he/she isn't a complete ***** then
    what did you get for ez isomer im sure there was only one ez isomer
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    (Original post by bagelbe)
    Do you think I'll get a mark for writing that hydrolysis with Cl occurs faster as polarity decreases down the group?
    I think so
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    (Original post by king1234)
    what did you get for ez isomer im sure there was only one ez isomer
    Yes exactly! I chose the one on the bottom left, I can't remember what the letter was though. It consisted of a C=C bond, one Hydrogen attached to each Carbon and then I think it was a CH3 group attached to each Carbon
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    (Original post by nereik6794)
    I think so
    Awesome
 
 
 
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