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SOLVED - Stuck on some C2 questions. Logarithms watch

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    So i'm beginning the fun process of revising for my summer maths exams.

    I'm aiming to try and get 90+% in both M1 and C2 as I epically failed my C1 exam by screwing the exam up completely (I didn't totally fail. I was one mark of an A )

    So I started by trying the exam paper in the back of my edexcel book and seem to be stuck on two questions which have confused me quite a bit.

    The first is logarithms:

    Given that
     \log_2 x =P
    Find  \log_2 (8x^2) in terms of P

    So I was thinking
     \log_2 (8x^2) = 2\log_2 x + \log_2 8 

= 2\log_2 x + 3
    But i'm really not sure where to go from here
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    (Original post by MinpoloD)
    So i'm beginning the fun process of revising for my summer maths exams.

    I'm aiming to try and get 90+% in both M1 and C2 as I epically failed my C1 exam by screwing the exam up completely (I didn't totally fail. I was one mark of an A )

    So I started by trying the exam paper in the back of my edexcel book and seem to be stuck on two questions which have confused me quite a bit.

    The first is logarithms:

    Given that
     \log_2 x =P
    Find  \log_2 (8x^2) in terms of P

    So I was thinking
     \log_2 (8x^2) = 2\log_2 x + \log_2 8 

= 2\log_2 x + 3
    But i'm really not sure where to go from here
    Well, since \log_2x = P;

    2\log_2x + 3 = 2P + 3

    Done.
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    you've done all the hard work, can't you see the subsitution?
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    (Original post by MinpoloD)
    So i'm beginning the fun process of revising for my summer maths exams.

    I'm aiming to try and get 90+% in both M1 and C2 as I epically failed my C1 exam by screwing the exam up completely (I didn't totally fail. I was one mark of an A )

    So I started by trying the exam paper in the back of my edexcel book and seem to be stuck on two questions which have confused me quite a bit.

    The first is logarithms:

    Given that
     \log_2 x =P
    Find  \log_2 (8x^2) in terms of P

    So I was thinking
     \log_2 (8x^2) = 2\log_2 x + \log_2 8 

= 2\log_2 x + 3
    But i'm really not sure where to go from here
    You are almost there
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    (Original post by Swayum)
    Well, since \log_2x = P;

    2\log_2x + 3 = 2P + 3

    Done.

    (Original post by HedonisticMe)
    you've done all the hard work, can't you see the subsitution?

    (Original post by steve2005)
    You are almost there
    Couldn't find the headslap smilie so you'll have to do with these guys

    :banghead: :doh:

    But thanks all I was just being a bit of a blind dim wit
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    I wish I could go back to studying C2.

    :weeps:
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    (Original post by MinpoloD)
    Couldn't find the headslap smilie so you'll have to do with these guys

    :banghead: :doh:

    But thanks all I was just being a bit of a blind dim wit
    :facepalm:
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    (Original post by tehforum)
    :facepalm:
    Ta.
 
 
 
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