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# Integration and Logarithm questions CIE AS Mathematics watch

1. (Original post by Prisonbreak94)
I sent you the PM.

Uhm so does it become [Tan(2x) - x] / 2 +k
I replied. You are getting closer but there is no reason why the x should now turn into x/2.
2. (Original post by Mr M)
I replied. You are getting closer but there is no reason why the x should now turn into x/2.
Hmm I had the /2 part from the tan(ax+b) /a + k thing...
3. (Original post by Prisonbreak94)
Hmm I had the /2 part from the tan(ax+b) /a + k thing...
Yes but why are you dividing x by 2?

It is a different term and you said you already understand that you can integrate each term separately.
4. (Original post by Mr M)
Yes but why are you dividing x by 2?

It is a different term and you said you already understand that you can integrate each term separately.
Okay, so from what you have said I am assuming it has to be:

[ Tan (2X) / 2 ] - x + k
5. (Original post by Prisonbreak94)
Okay, so from what you have said I am assuming it has to be:

[ Tan (2X) / 2 ] - x + k
yes now you need to do the limits - obviously you can forget about the + k when you do that
6. (Original post by Mr M)
yes now you need to do the limits - obviously you can forget about the + k when you do that
Thank you!

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