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Integration and Logarithm questions CIE AS Mathematics Watch

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    (Original post by Prisonbreak94)
    I sent you the PM.

    Uhm so does it become [Tan(2x) - x] / 2 +k
    I replied. You are getting closer but there is no reason why the x should now turn into x/2.
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    (Original post by Mr M)
    I replied. You are getting closer but there is no reason why the x should now turn into x/2.
    Hmm I had the /2 part from the tan(ax+b) /a + k thing...
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    (Original post by Prisonbreak94)
    Hmm I had the /2 part from the tan(ax+b) /a + k thing...
    Yes but why are you dividing x by 2?

    It is a different term and you said you already understand that you can integrate each term separately.
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    (Original post by Mr M)
    Yes but why are you dividing x by 2?

    It is a different term and you said you already understand that you can integrate each term separately.
    Okay, so from what you have said I am assuming it has to be:

    [ Tan (2X) / 2 ] - x + k
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    (Original post by Prisonbreak94)
    Okay, so from what you have said I am assuming it has to be:

    [ Tan (2X) / 2 ] - x + k
    yes now you need to do the limits - obviously you can forget about the + k when you do that
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    (Original post by Mr M)
    yes now you need to do the limits - obviously you can forget about the + k when you do that
    Thank you!
 
 
 
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