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# Making a sucrose solution with a specific concentration watch

1. If I'm given a solution containing sucrose (0.55 mol dm-3, 50cm3), and required to make a sucrose solution with a concentration of 3.2 x 10-2 mol dm-3, will I do that by changing the volume as follows?

C1 x V1 = C2 X V2

0.55 mol dm-3 x 0.05 dm-3 = 3.2 x 10-2 mol dm-3 x V2

V2 = 0.8594 dm-3

So, can we say that in order to make a sucrose solution with a concentration of 3.2 x 10-2 mol dm-3, we need V2-V2 dm-3? That is, 0.8594 dm-3 - 0.05 dm-3 = 0.8094 dm-3?

Is it right that way?

Thanks.
2. Get 0.0032 mols of sucrose, then make upto the mark of 1 litre with distilled water.

EDIT: Woops didn't read the rest
3. (Original post by thegodofgod)
Get 0.0032 mols of sucrose, then make upto the mark of 1 litre with distilled water.

EDIT: Woops didn't read the rest

I forgot to mention that I have 50cm3 of sucrose, but was shown when applying the equation.

So, is my solution correct that way?
4. (Original post by SWEngineer)

I forgot to mention that I have 50cm3 of sucrose, but was shown when applying the equation.

So, is my solution correct that way?
Sorry, I'm not too sure - but it does sound right. Haven't done this before
5. (Original post by thegodofgod)
Sorry, I'm not too sure - but it does sound right. Haven't done this before
I see. That's fine.

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