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Making a sucrose solution with a specific concentration

If I'm given a solution containing sucrose (0.55 mol dm-3, 50cm3), and required to make a sucrose solution with a concentration of 3.2 x 10-2 mol dm-3, will I do that by changing the volume as follows?

C1 x V1 = C2 X V2


0.55 mol dm-3 x 0.05 dm-3 = 3.2 x 10-2 mol dm-3 x V2

V2 = 0.8594 dm-3

So, can we say that in order to make a sucrose solution with a concentration of 3.2 x 10-2 mol dm-3, we need V2-V2 dm-3? That is, 0.8594 dm-3 - 0.05 dm-3 = 0.8094 dm-3?

Is it right that way?

Thanks.
(edited 13 years ago)
Get 0.0032 mols of sucrose, then make upto the mark of 1 litre with distilled water.

EDIT: Woops didn't read the rest :colondollar: :mmm:
(edited 13 years ago)
Reply 2
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SWEngineer
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Original post by thegodofgod
Get 0.0032 mols of sucrose, then make upto the mark of 1 litre with distilled water.

EDIT: Woops didn't read the rest :colondollar: :mmm:


Thanks for your reply.

I forgot to mention that I have 50cm3 of sucrose, but was shown when applying the equation.

So, is my solution correct that way?
Original post by SWEngineer
Thanks for your reply.

I forgot to mention that I have 50cm3 of sucrose, but was shown when applying the equation.

So, is my solution correct that way?


Sorry, I'm not too sure - but it does sound right. Haven't done this before :redface:
Reply 4
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SWEngineer
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Original post by thegodofgod
Sorry, I'm not too sure - but it does sound right. Haven't done this before :redface:


I see. That's fine.

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