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Making a sucrose solution with a specific concentration watch

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    If I'm given a solution containing sucrose (0.55 mol dm-3, 50cm3), and required to make a sucrose solution with a concentration of 3.2 x 10-2 mol dm-3, will I do that by changing the volume as follows?

    C1 x V1 = C2 X V2

    0.55 mol dm-3 x 0.05 dm-3 = 3.2 x 10-2 mol dm-3 x V2

    V2 = 0.8594 dm-3

    So, can we say that in order to make a sucrose solution with a concentration of 3.2 x 10-2 mol dm-3, we need V2-V2 dm-3? That is, 0.8594 dm-3 - 0.05 dm-3 = 0.8094 dm-3?

    Is it right that way?

    Thanks.
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    Get 0.0032 mols of sucrose, then make upto the mark of 1 litre with distilled water.

    EDIT: Woops didn't read the rest :mmm:
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    (Original post by thegodofgod)
    Get 0.0032 mols of sucrose, then make upto the mark of 1 litre with distilled water.

    EDIT: Woops didn't read the rest :mmm:
    Thanks for your reply.

    I forgot to mention that I have 50cm3 of sucrose, but was shown when applying the equation.

    So, is my solution correct that way?
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    (Original post by SWEngineer)
    Thanks for your reply.

    I forgot to mention that I have 50cm3 of sucrose, but was shown when applying the equation.

    So, is my solution correct that way?
    Sorry, I'm not too sure - but it does sound right. Haven't done this before
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    (Original post by thegodofgod)
    Sorry, I'm not too sure - but it does sound right. Haven't done this before
    I see. That's fine.
 
 
 
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