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# Group Theory watch

1. Hey guys,
Ive got a problem here:
how would i find the normalisers of (1)(23) & (123) in S3?

2. You could start by searching for the other threads (presumably from people at your uni) asking this...
3. The normalizer N(S) are all x those such that xS=Sx. Just a case of trying out all the possibilities.

So if A=(1)(23)
and B=(123)
and id=(1)(2)(3)

N(A) = {id, (1)(23)}
N(B) = {id, (123) , (321) }
4. is s3 the symmetric group on 3 letters?

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Updated: April 10, 2011
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