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    Hey guys,
    Ive got a problem here:
    how would i find the normalisers of (1)(23) & (123) in S3?

    Thanks in advance
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    You could start by searching for the other threads (presumably from people at your uni) asking this...
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    The normalizer N(S) are all x those such that xS=Sx. Just a case of trying out all the possibilities.

    So if A=(1)(23)
    and B=(123)
    and id=(1)(2)(3)

    N(A) = {id, (1)(23)}
    N(B) = {id, (123) , (321) }
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    is s3 the symmetric group on 3 letters?
 
 
 
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Updated: April 10, 2011
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