Hey there! Sign in to join this conversationNew here? Join for free
    • Thread Starter


    Question 11(ii).

    I see that, by the JCF theorem, it's enough to show that a Jordan block J_n(x) has a square root. But how would I find the square root of this matrix? Obviously the leading diagonal will have x^0.5, but what would I choose for the rest of the entries? I couldn't even do it in the 2x2 case!

    I would take an arbitrary Jordan block, calculate the square, and then "reverse engineer" what the square root must be. (Doing a couple of concrete examples for the 2x2 case might help). I don't think it's very difficult.
Do you agree with the PM's proposal to cut tuition fees for some courses?
Useful resources

Make your revision easier


Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here


How to use LaTex

Writing equations the easy way

Student revising

Study habits of A* students

Top tips from students who have already aced their exams

Study Planner

Create your own Study Planner

Never miss a deadline again

Polling station sign

Thinking about a maths degree?

Chat with other maths applicants

Can you help? Study help unanswered threads

Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.