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    Hey,

    I was wondering if someone could help me with question 8 of the C1 January 2005 paper.
    It looks pretty straight forward; but i'm just not getting it.
    At the moment part (a) is what I need help on; I know the answers, just not clear on the working out.
    Here's the link to the paper; http://www.scribd.com/doc/10513746/C1-Jan-05

    Any help is greatly appreciated
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    D is the midpoint of A and C so however far right you move from A to D, double it and thats the X coordinate. However far down you move from A to D, double it and work out how far below the X axis it would be and thats the Y coordinate. I don't know whether that explained it well but it's as simple as I could put it.
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    (Original post by iitsMee..x)
    Hey,

    I was wondering if someone could help me with question 8 of the C1 January 2005 paper.
    It looks pretty straight forward; but i'm just not getting it.
    At the moment part (a) is what I need help on; I know the answers, just not clear on the working out.
    Here's the link to the paper; http://www.scribd.com/doc/10513746/C1-Jan-05

    Any help is greatly appreciated
    What's the formula for the midpoint of a line where you know both sets of coordinates?
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    D is the midpoint of AC. The formula for a midpoint is (x,y) = (\dfrac{x_2-x_1}{2}, \dfrac{y_2-y_1}{2}). Plug some numbers in and Bob's your uncle.
    Or alternatively, do it the way mentioned above.
 
 
 
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