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    A mass of 10kg, resting on a rough table at a distance 3m from the edge, is connected by a string to a 5kg mass hanging vertically. The system starts from rest and after 2 seconds the 10kg mass reaches the edge of the table.

    a) Find the acceleration of the masses

    s= 1/2(u + v)t

    3 = 1/2(0 + v)2

    3 = 1 (0 + v)

    3 = v

    v^2 = u^2 + 2as

    3^2 = 0^2 + 2as

    9 = 2a3

    9 = 6a

    a = 1.5


    b)Find the frictional force acting on the 10kg mass and show the coefficient of friction is 0.27


    I need help with this one, I know I need to find F and divide by R (98N) to find the coefficient of friction, but I can't find "F"
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    Use F-R = ma
    The particle you are interested in is being pulled by a mass of 5kg, and as this is moving vertically down you can work out the force that it is exerting on your particle. You also know m and a, which means you can work out R.
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    5g-Fr=ma

    Calculate a through s=ut +1/2 at^2 and m is 10g
 
 
 
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Updated: April 11, 2011
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