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# Iteration of a quadratic watch

1. (Original post by Mr M)
Plato pm me with an email address and I will send you a Powerpoint and a .pdf of some worksheets that will help your understanding.
Oh hang on...sorry, I am being dim.

I already identified the two fixed points and determined that -5/6 was the only attracting fixed point. And since x=0 is in its interval of attraction, an iteration starting with x=0 must converge to -5/6

Simple as that, right?

I think I was overcomplicating things!
2. (Original post by Plato's Trousers)
Oh hang on...sorry, I am being dim.

I already identified the two fixed points and determined that -5/6 was the only attracting fixed point. And since x=0 is in its interval of attraction, an iteration starting with x=0 must converge to -5/6

Simple as that, right?

I think I was overcomplicating things!
Yes sounds like you have it sorted.
3. Thanks

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