I'm only familiar with curve sketching involving trigonometry in polar.. How to draw this? I get that r=0 at theta=pi/2 and pi^2/4 at theta=pi/2 but how do I determine the shape, etc. Do I differentiate dr/dtheta to find the turning point? The mark scheme shows 'Negative gradient at A; Correct form at O.', what does A and O stand for?
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Sketching the curve of r = (pi/2 - theta)^2 watch
- Thread Starter
- 11-04-2011 18:06
- 11-04-2011 18:07
just plug a few points on your calculator and make a rough sketch.
then if need be differentiate it to work out turning/inflexion points and mark them on.
then check what happens when x -> +infinity.
those are generally the basic steps to sketching a random function (depending on the function you may want to check for asymptotes too)Last edited by didgeridoo12uk; 11-04-2011 at 18:13.