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# Rectilinar Motion watch

1. http://www.xtremepapers.net/Edexcel/...%20Physics.pdf

How do I answer Q3c)

I know the answer is "same average velocity" but I don't know why
2. ___
would I calculate area under graph for both (distance) and compare with time?
3. (Original post by jsmith6131)
___
would I calculate area under graph for both (distance) and compare with time?
The average velocity in this case will be the total distance travelled divided by the total time taken. So yes, it's the total area under the graphs (=distance travelled) divided by the time taken. As the time taken is the same it's just the relationship between those two areas.
I haven't measured them but if they are the same then the avarage velocities were the same in that time interval.

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