Turn on thread page Beta
    • Thread Starter
    Offline

    0
    ReputationRep:
    Hey, I really need urgent help with this chemistry problem.

    How would I dilute 0.005M iodine solution to 0.004, then from 0.004 to 0.003 etc.? What factor do I dilute it by? It's probably straightforward but I dont know how to do it. I can't ask my chem teacher because I'm on my holidays...

    Thank you so much!
    Offline

    19
    Say if you had 5 ml of 0.005M you can take 4 ml of this solution and add 1 ml of water to it to get 5ml of 0.004M. Make sense?
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by EierVonSatan)
    Say if you had 5 ml of 0.005M you can take 4 ml of this solution and add 1 ml of water to it to get 5ml of 0.004M. Make sense?
    Ah, I see, I see...lol that sounds simple

    So then to make 0.003 from 0.004 you just take 3 ml of this solution and add 1 ml of water to it? And then you keep doing that? I feel I'm missing something major here...

    Does m1v1 = m2v2 come into this? So say if I had 25cm3 of 0.004M then to get 0.003M I would need 33.3 cm3 of water?
    Offline

    19
    (Original post by Gooner786)
    Ah, I see, I see...lol that sounds simple
    I made the volumes simple

    So then to make 0.003 from 0.004 you just take 3 ml of this solution and add 1 ml of water to it? And then you keep doing that? I feel I'm missing something major here...
    Nope, that's not right.

    Does m1v1 = m2v2 come into this? So say if I had 25cm3 of 0.004M then to get 0.003M I would need 33.3 cm3 of water?
    I don't ever recall using that equation...you mean concentration = moles/volume?

    All you have to do is keep perspective on the number of moles you have :yes:

    So 25cm3 of 0.004 M = 0.0001 moles

    concentration you want = 0.003 M so the volume you need is indeed 33.3 cm3
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by EierVonSatan)
    I made the volumes simple



    Nope, that's not right.



    I don't ever recall using that equation...you mean concentration = moles/volume?

    All you have to do is keep perspective on the number of moles you have :yes:

    So 25cm3 of 0.004 M = 0.0001 moles

    concentration you want = 0.003 M so the volume you need is indeed 33.3 cm3
    Ahh I see...

    One last thing (sorry for the questions lol), but 33.3 cm3 is the volume of 0.003M solution I need. What I'm wondering is how much water I need to add to the 25cm3 of 0.004M solution to obtain 0.003M...so would that just be 33.3-25 = 8.3cm3 of water?

    Thanks so far by the way, youve been a great help

    EDIT: I might be overcomplicating things...
    Offline

    19
    (Original post by Gooner786)
    Ahh I see...

    One last thing (sorry for the questions lol), but 33.3 cm3 is the volume of 0.003M solution I need. What I'm wondering is how much water I need to add to the 25cm3 of 0.004M solution to obtain 0.003M...so would that just be 33.3-25 = 8.3cm3 of water?

    Thanks so far by the way, youve been a great help

    EDIT: I might be overcomplicating things...
    Yep, just the simple subtraction will get you the amount of water you need to add
    • Thread Starter
    Offline

    0
    ReputationRep:
    (Original post by EierVonSatan)
    Yep, just the simple subtraction will get you the amount of water you need to add
    Awesome! Thanks for all the help!
 
 
 
Reply
Submit reply
Turn on thread page Beta
Updated: April 13, 2011
The home of Results and Clearing

1,621

people online now

1,567,000

students helped last year

University open days

  1. Bournemouth University
    Clearing Open Day Undergraduate
    Fri, 17 Aug '18
  2. University of Bolton
    Undergraduate Open Day Undergraduate
    Fri, 17 Aug '18
  3. Bishop Grosseteste University
    All Courses Undergraduate
    Fri, 17 Aug '18
Poll
Will you be tempted to trade up and get out of your firm offer on results day?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reply
Hide
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.