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# Chemistry Dilution Problem watch

1. Hey, I really need urgent help with this chemistry problem.

How would I dilute 0.005M iodine solution to 0.004, then from 0.004 to 0.003 etc.? What factor do I dilute it by? It's probably straightforward but I dont know how to do it. I can't ask my chem teacher because I'm on my holidays...

Thank you so much!
2. Say if you had 5 ml of 0.005M you can take 4 ml of this solution and add 1 ml of water to it to get 5ml of 0.004M. Make sense?
3. (Original post by EierVonSatan)
Say if you had 5 ml of 0.005M you can take 4 ml of this solution and add 1 ml of water to it to get 5ml of 0.004M. Make sense?
Ah, I see, I see...lol that sounds simple

So then to make 0.003 from 0.004 you just take 3 ml of this solution and add 1 ml of water to it? And then you keep doing that? I feel I'm missing something major here...

Does m1v1 = m2v2 come into this? So say if I had 25cm3 of 0.004M then to get 0.003M I would need 33.3 cm3 of water?
4. (Original post by Gooner786)
Ah, I see, I see...lol that sounds simple

So then to make 0.003 from 0.004 you just take 3 ml of this solution and add 1 ml of water to it? And then you keep doing that? I feel I'm missing something major here...
Nope, that's not right.

Does m1v1 = m2v2 come into this? So say if I had 25cm3 of 0.004M then to get 0.003M I would need 33.3 cm3 of water?
I don't ever recall using that equation...you mean concentration = moles/volume?

All you have to do is keep perspective on the number of moles you have

So 25cm3 of 0.004 M = 0.0001 moles

concentration you want = 0.003 M so the volume you need is indeed 33.3 cm3
5. (Original post by EierVonSatan)

Nope, that's not right.

I don't ever recall using that equation...you mean concentration = moles/volume?

All you have to do is keep perspective on the number of moles you have

So 25cm3 of 0.004 M = 0.0001 moles

concentration you want = 0.003 M so the volume you need is indeed 33.3 cm3
Ahh I see...

One last thing (sorry for the questions lol), but 33.3 cm3 is the volume of 0.003M solution I need. What I'm wondering is how much water I need to add to the 25cm3 of 0.004M solution to obtain 0.003M...so would that just be 33.3-25 = 8.3cm3 of water?

Thanks so far by the way, youve been a great help

EDIT: I might be overcomplicating things...
6. (Original post by Gooner786)
Ahh I see...

One last thing (sorry for the questions lol), but 33.3 cm3 is the volume of 0.003M solution I need. What I'm wondering is how much water I need to add to the 25cm3 of 0.004M solution to obtain 0.003M...so would that just be 33.3-25 = 8.3cm3 of water?

Thanks so far by the way, youve been a great help

EDIT: I might be overcomplicating things...
Yep, just the simple subtraction will get you the amount of water you need to add
7. (Original post by EierVonSatan)
Yep, just the simple subtraction will get you the amount of water you need to add
Awesome! Thanks for all the help!

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