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    Hi all,
    I can't seem to get the correct answer to this question- help please!!
    The region R in the x-y plane is bounded by y=sinhx, the x-axis and the line AB which is perpendicular to the x-axis.
    Given that AB=0.75, show that OB=ln3.

    So I put y=0.75 into y=sinhx and rearrange to get arcsinh0.75=x
    Then I use the logarithmic form to solve and get ln2… I must be doing something stupid: can somebody please tell me what!?!?

    Regards,
    Bently7
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    (Original post by Bently7)
    Hi all,
    I can't seem to get the correct answer to this question- help please!!
    The region R in the x-y plane is bounded by y=sinhx, the x-axis and the line AB which is perpendicular to the x-axis.
    Given that AB=0.75, show that OB=ln3.

    So I put y=0.75 into y=sinhx and rearrange to get arcsinh0.75=x
    Then I use the logarithmic form to solve and get ln2… I must be doing something stupid: can somebody please tell me what!?!?

    Regards,
    Bently7
    If B's on the x-axis, then ln2 seems correct. If you sub ln2 back into the defn of y you get 3/4.
 
 
 
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