I'm going through OCR past exams, and on the June 07 exam, question 2, I managed to confuse myself slightly. The question is:
"Calculate the range on a horizontal plane of a small stone projected from a point on the plane with speed 12 m/s at an angle of elevation of 27 degrees."
So I got the answer pretty quickly, by finding how long it took to get to the top of its path where v=o, vertically. Using v^2 =u^2 + 2as, where v=0, u=12sin27, a=-9.8, I found s to be 1.514. From there I just found the time according to v=u+at, doubled it for time of flight, and plugged that time into the horizontal s=ut+1/2 at^2.
My question is from the part where I found the vertical displacement when v=o. Surely there are two points when v=o; at the top of its path, and at the end of the path. Should I not get another answer for s (0)?