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    Hey, Im a GCSE student and today within my revision I came across quite a confusing question using dot and cross diagrams:

    It was to show the electron configuration of the ions when Aluminium reacts with Bromine.


    The bromine config, i was going to draw another 2, would this be correct?
    Have I arranged the elctrons incorrectly?

    thank you
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    A bromine atom has 7 outer electrons (it's in group 7) so getting one from Al completes the outer shell, but yes you will need three of these
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    Thats what I dont understand, Shouldn't the formation be 2,8,8,8,8 1 = 35 right?

    Thats saying it has 1 in the outshell

    Like for aluminium its 2,8,3 and its in group 3....
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    The actual electronic configuration for larger atoms is a bit more complicated than what you're taught at GCSE, I'm afraid.

    Bromine is actually 2, 8, 8, 17 but all you need to really understand is that the outer shell has 7 electrons and needs 1 more to complete the shell
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    The bromine ion needs a negative charge as well, rather than positive.
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    I missed that :facepalm:
 
 
 
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