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# PD Between two charged plates watch

1. Stupid question, nonetheless, I will ask it :

Supposing I have two charged plates set up with a gap of a distance of xm between them.

These plates are parallel and the elctric field between them is uniform.

Supposing the PD on one plate is +5V and the other is -5V.

What is the electric field strength in terms of x ?
2. Hello ?
3. The field strength is always the potential difference divided by the distance between the two plates for a parallel plate capacitor.
4. (Original post by Stonebridge)
The field strength is always the potential difference divided by the distance between the two plates for a parallel plate capacitor.
Yes, I know that.

Why is the answer 10/x ??

Could you look at this please :

http://www.thestudentroom.co.uk/show...7#post30858767
5. because the formula is E = v/d
6. (Original post by Firewalker123)
because the formula is E = v/d
Yes I know that, but shouldnt it be 5/x ??
7. (Original post by Ari Ben Canaan)
Yes, I know that.

Why is the answer 10/x ??
Because the potential difference is 10V.
8. (Original post by Stonebridge)
Because the potential difference is 10V.
Ahhhhh..... I see now.

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