# Maths Coursework

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#1
Hi, i am doing a piece of investigative courswork, on T-Totals in Maths. You have to use a 9x9 gird, and draw a T shape, consisting of 3x2 squares. Then you have to find a T-number, which is the number at the bottom of the T and then a T-total, which is all of the numbers inside of the T, example,

Blue T-Shape: 6+7+8+16+25=62
The T-Number is: 25
The T-Total is: 62

Then you have to find a connection between the T-Number, and the T-Total. this is the part i am having trouble with.

If anyone is doing the same piece of courswork, or anyone could give me any tips then i would be very grateful.

Thank you, Love Sophie
0
16 years ago
#2
hi yeah it took me a while, try 5t-7g. g being the width of the grid and t being the t-number.
0
16 years ago
#3
Hi Sophie,
I wonder if you have solved your problem. The answer is Given a T number, the Total will be 5T-63.

Working: Take any T. The SUM in Vertical Row of the T is 3xMiddle Number. The Middle Number is always T-9.

The SUM of the Horizontal Row is 3xMiddle Number. This Middle number is always T-18. But the Middle number in the Horizontal is already counted when ones does the Vertical addition.

So we have SUM inside a T = (T-9)x3 + (T-18)x2
Simplify this and you get SUM = 5T-63

Hope this helps.
Regards / Bala Uncle from Singapore
0
16 years ago
#4
this is easier:

if you look at the t-shape for example:

1 2 3
11
20

This is the same as:

20-19 20-18 20-17
20-9
20-0

or...

n-19 n-18 n-17
n-9
n-0

n is the t-number

if you add up all of those, e.g,

(n-19)+(n-18)+(n-17)+(n-9)+(n-0)

you get:

5n - 63

That is the method most people use, i don't know whether you would understand how i put it cos im not that good at explaining myself, but i found the method quite easy. you can use that method in other calculations aswell, for example when you have to find the t-total from the grid size and t-number (you change the 63 into something like 5g - thats not the answer i just made it up)

i hate the courswork at the moment i am REALLY stuck on part 3- where you have to do rotation (which ive done) reflection, enlargement, transformation (which i think ive done) .

can anyone help?
0
16 years ago
#5
(Original post by Unregistered)
this is easier:

if you look at the t-shape for example:

1 2 3
11
20

This is the same as:

20-19 20-18 20-17
20-9
20-0

or...

n-19 n-18 n-17
n-9
n-0

n is the t-number

if you add up all of those, e.g,

(n-19)+(n-18)+(n-17)+(n-9)+(n-0)

you get:

5n - 63

That is the method most people use, i don't know whether you would understand how i put it cos im not that good at explaining myself, but i found the method quite easy. you can use that method in other calculations aswell, for example when you have to find the t-total from the grid size and t-number (you change the 63 into something like 5g - thats not the answer i just made it up)

i hate the courswork at the moment i am REALLY stuck on part 3- where you have to do rotation (which ive done) reflection, enlargement, transformation (which i think ive done) .

can anyone help?
I might be able to help you with the rotation cuz ive already done it. I can't seem to get the enlargement formula so maybe we could help each other? Could you send me the formula and ill give you the rotoation formula.Thanx
0
15 years ago
#6
5t-63 only work with the 9 by 9 grid size. If you change the size to 8 by 8, the formula will be 5t-56, and if it was 7 by 7, the formula will change to 5t-49.
That's why the general formula (work with every grid sizes) is 5t-7G. G is the grid size i.e. on 9by9 table, G=9. On 7 by 7, G=7. 6 by 6, G=6...

That what the part 1 is, and the second formula for part 2 is 5(T+a-bG)-7G. I'm still thinking 'bout the 3rd part
0
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