# Fp1 Help Series QuestionWatch

#1
teacher gave me the jan 11 paper to try and there's a question on series that i'm struggling with (the part I can't do isn't really related to that topic area however).

Its part 8c, just not sure how to solve the cubic or maybe i'm just over thinking. Thaks for any help!

0
7 years ago
#2
8c) If you continue the iteration in part (a) this will give the solitary real root.
So N will be the lowest integer greater than this root.
0
#3
(Original post by vc94)
8c) If you continue the iteration in part (a) this will give the solitary real root.
So N will be the lowest integer greater than this root.
So am I working out the value of x3?? I got 45.8 so does that mean N is 45? or am I doing that completely wrong, I just dont understand why that would be what you have to do?? Sorry if i'm being a real pain.
0
7 years ago
#4
You have a cubic graph passing through root 45.8.
The inequality is >0 so you're interested in the part above the y-axis. So the solution is N>45.8 hence N must be 46.
0
#5
(Original post by vc94)
You have a cubic graph passing through root 45.8.
The inequality is >0 so you're interested in the part above the y-axis. So the solution is N>45.8 hence N must be 46.
ahhh now I get it, thank you!!
0
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