C4 differential Equations Help!! Watch

Sankey
Badges: 0
Rep:
?
#1
Report Thread starter 7 years ago
#1
i understand that if you have

dy/dx = xy this becomes: 1/y dy/dx = x

no problem here.

However, when they start involving number as well as constants i don't know were to move things

for example:

-10 dv/dx = v - 200

and

dv/dt = 1000/(2t+1)^2

could someone please clarify what has to be done when they involve constants combined with numbers
0
reply
rosschambers1987
Badges: 0
Rep:
?
#2
Report 7 years ago
#2
The first one, you can divide both sides by (v-200) and multiply both sides by dx so you have

-10/(v-200) dv = 1 dx

Then divide both by -10 so you have 1/(v-200) dv = -1/10 dx then you can integrate.

On the second one can you not just multiply both sides by dt and then integrate so you would have 1 dv = 1000/(2t+1)^2 dt

Which would be v = -500/(2t +1) + c?

PS - I'm taking my c4 exam in June
0
reply
X

Quick Reply

Attached files
Write a reply...
Reply
new posts
Latest
My Feed

See more of what you like on
The Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

Personalise

University open days

  • Cranfield University
    Cranfield Forensic MSc Programme Open Day Postgraduate
    Thu, 25 Apr '19
  • University of the Arts London
    Open day: MA Footwear and MA Fashion Artefact Postgraduate
    Thu, 25 Apr '19
  • Cardiff Metropolitan University
    Undergraduate Open Day - Llandaff Campus Undergraduate
    Sat, 27 Apr '19

Have you registered to vote?

Yes! (125)
39.56%
No - but I will (17)
5.38%
No - I don't want to (20)
6.33%
No - I can't vote (<18, not in UK, etc) (154)
48.73%

Watched Threads

View All