# OCR MEI Numerical Methods RevisionWatch

Thread starter 7 years ago
#1
Hey there guys, my exam is coming up in a few weeks and I keep getting stuck on the same kind of questions and the book I have is not very good.

Are there any websites with revision material for this exam board?
0
7 years ago
#2
try the website mei.org.uk i think (just type mei into google and its the first one). They have some revision resources i think. Yes the book is terrible, just make sure you do the past papers as well (on the site if u need them) because thats probably the best way to revise for Alevel maths exam IMO.
0
7 years ago
#3
Hi, i need some clarification before the exam tommorow,
the mark schemes give the answers to 6 d.p
but sometimes futher calculations using the answers to 6 d.p gives the answers wrong for example
http://www.mei.org.uk/files/papers/nm09ju_20cs.pdf
in question 6 for the second part the second simpsons rule estimate is 1.428017 when using the midpoint rule as 1.431056 ( 6 d.p) but when you use the midpoint rule as 1.43015560 you get the simpsons rule estimate as 1.428016 which is the correct answer

my question is , do we have to state the answers to 6 d.p or can we put more down for questions like numerical integration.
0
7 years ago
#4
(Original post by supercal35)
Hi, i need some clarification before the exam tommorow,
the mark schemes give the answers to 6 d.p
but sometimes futher calculations using the answers to 6 d.p gives the answers wrong for example
http://www.mei.org.uk/files/papers/nm09ju_20cs.pdf
in question 6 for the second part the second simpsons rule estimate is 1.428017 when using the midpoint rule as 1.431056 ( 6 d.p) but when you use the midpoint rule as 1.43015560 you get the simpsons rule estimate as 1.428016 which is the correct answer

my question is , do we have to state the answers to 6 d.p or can we put more down for questions like numerical integration.
Your best option is to just store the values into your calculator so that you can use the the full values (to avoid rounding errors) for further calculations.
0
6 years ago
#5
how did you guys find it then?
0
6 years ago
#6
I reckon it was harder than usual (well more strenuous particularly with both the secant method and method of false position - fml) and there were odd bits here and there that seemed completely different to past papers.

By the way, for the method of false position, you guys did take each iteration with two values of x that form an interval of the root right?
0
6 years ago
#7
(Original post by Reminisce)
I reckon it was harder than usual (well more strenuous particularly with both the secant method and method of false position - fml) and there were odd bits here and there that seemed completely different to past papers.

By the way, for the method of false position, you guys did take each iteration with two values of x that form an interval of the root right?
Yeah I did that as in found my initial estimate, did f at that root then saw positive or negative therefore root must be between these two..

What did you do for the simpsons rule from trapezium one, did u calculate midpoint rule estimates?
0
6 years ago
#8
For discussion of today's exam: http://www.thestudentroom.co.uk/show....php?t=1981740
0
6 years ago
#9
Did all your functions of x in false position come out negative so you kept using the interval -1 and the new x?

Midpoint I found by the T2n = (Tn + Mn)/2 formula but rearranged.
0
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