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some simple integration problems that i cant seem to do...! watch

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    integrate with respect to x
    a) 4/√x + 3/x³
    b) 6x(1+x²)^½

    show that the substitution x=u² transforms ∫(limits 4 to 1) (1+√x)³/√x dx into an integral of the form ∫ (limits b to a) k(1+u)³du

    that the value ok k, a and b. evaluate this integral
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    integrate with respect to x
    a) 4/√x + 3/x³
    b) 6x(1+x²)^½

    show that the substitution x=u² transforms ∫(limits 4 to 1) (1+√x)³/√x dx into an integral of the form ∫ (limits b to a) k(1+u)³du

    that the value ok k, a and b. evaluate this integral
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    (Original post by idiosyncratic88)
    integrate with respect to x
    a) 4/√x + 3/x³
    b) 6x(1+x²)^½

    show that the substitution x=u² transforms ∫(limits 4 to 1) (1+√x)³/√x dx into an integral of the form ∫ (limits b to a) k(1+u)³du

    that the value ok k, a and b. evaluate this integral
    a)

    ∫4/√x + 3/x³ dx = ∫4x^-0.5 + 3x^-3 dx = 8x^0.5 - 1.5x^-2 + c

    b)

    ∫ 6x(1+x²)^½ dx = 2∫ 3x(1+x²)^½ dx = 2(1+x^2)^1.5 + c

    c)

    ∫(1+√x)³/√x dx

    k=u^2

    ∫(1+u)³/u du = ∫1/u + 3 + 3u + u^2 du =
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    (Original post by idiosyncratic88)
    integrate with respect to x
    a) 4/√x + 3/x³
    b) 6x(1+x²)^½

    show that the substitution x=u² transforms ∫(limits 4 to 1) (1+√x)³/√x dx into an integral of the form ∫ (limits b to a) k(1+u)³du

    that the value ok k, a and b. evaluate this integral
    a)

    ∫4/√x + 3/x³ dx = ∫4x^-0.5 + 3x^-3 dx = 8x^0.5 - 1.5x^-2 + c

    b)

    ∫ 6x(1+x²)^½ dx = 2∫ 3x(1+x²)^½ dx = 2(1+x^2)^1.5 + c

    c)

    ∫(1+√x)³/√x dx

    k=u^2

    ∫(1+u)³/u du = ∫1/u + 3 + 3u + u^2 du =
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    a) ∫(4/√x + 3/x³)dx

    = ∫(4x-1/2 + 3x-3)dx

    = 8x1/2 - 3x-2/2 + c

    I think ...

    Hope this helps,

    ~~Simba
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    a) ∫(4/√x + 3/x³)dx

    = ∫(4x-1/2 + 3x-3)dx

    = 8x1/2 - 3x-2/2 + c

    I think ...

    Hope this helps,

    ~~Simba
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    ooh thanks!!! ill probably have loads more integrations Qu's that i'll need help with coming up!! if u like 'em ive got loads to give ya!
    thanks again
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    ooh thanks!!! ill probably have loads more integrations Qu's that i'll need help with coming up!! if u like 'em ive got loads to give ya!
    thanks again
 
 
 
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