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Reply 1
1/sec(x) = 1/[1/cos(x)] = cos(x)
Reply 5
Reciprical means 1/, so the reciprical of cos is 1/cos, or the reciprical of sec is cos.
The inverse of a function f(x) is defined to be f-1(x) such that f[f-1(x)]=x (and likewise f-1[f(x)] = x for obvious reasons).
The function which is f-1(x) when f(x)=sec(x) is arcsec(x), since sec[arcsec(x)] = x (for certain ranges of x).
The inverse of a function f(x) is defined to be f-1(x) such that f[f-1(x)]=x (and likewise f-1[f(x)] = x for obvious reasons).
The function which is f-1(x) when f(x)=sec(x) is arcsec(x), since sec[arcsec(x)] = x (for certain ranges of x).
Reply 6
AlphaNumeric
Reciprical means 1/, so the reciprical of cos is 1/cos, or the reciprical of sec is cos.
The inverse of a function f(x) is defined to be f-1(x) such that f[f-1(x)]=x (and likewise f-1[f(x)] = x for obvious reasons).
The function which is f-1(x) when f(x)=sec(x) is arcsec(x), since sec[arcsec(x)] = x (for certain ranges of x).
The inverse of a function f(x) is defined to be f-1(x) such that f[f-1(x)]=x (and likewise f-1[f(x)] = x for obvious reasons).
The function which is f-1(x) when f(x)=sec(x) is arcsec(x), since sec[arcsec(x)] = x (for certain ranges of x).
thanks alpha numeric this is what i meant.
so for example sec-1 1=0
by the way guys i am a girl
Reply 7
One relation connecting them is
arcsec(x) = arccos(1/x)
arcsec(x) = arccos(1/x)
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