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C2 - Exercise 11c - Q.5 - Answer?? watch

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    As above really...need help....not getting actual answer...
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    Textbook? Post the question here please, bearing in mind most people probably won't have the same textbook as you !
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    Sketch the following and find the area of the finite region or regions bounded by the curves and the x-axis: y = x (x - 2) (x - 5) .

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    Anyone for the above listed question...?
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    (Original post by lgeerthan)
    Anyone for the above listed question...?
    curve cuts x-axis at x= 0,2,5. Sketch curve.
    Enclosed area, therefore limits, between x=2 and x=0

    ∫x³ -7x² +10x dx
    =¼x^4 -(7/3)x³+5x²
    limits 2 and 0 give

    4 -(56/3) +20 = 16/3
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    (Original post by Aitch)
    curve cuts x-axis at x= 0,2,5. Sketch curve.
    Enclosed area, therefore limits, between x=2 and x=0

    ∫x³ -7x² +10x dx
    =¼x^4 -(7/3)x³+5x²
    limits 2 and 0 give

    4 -(56/3) +20 = 16/3
    And then isnt there a limit of 2 and 5??
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    (Original post by lgeerthan)
    And then isnt there a limit of 2 and 5??
    Oops! Yes!

    ¼x^4 -(7/3)x³+5x²
    limits 5 and 2 give

    [(625/4)-(875/3)+125]-[16/3]
    =(-)15.75
 
 
 
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