# A2 Physics: Circular Motion Help

This discussion is closed.
#1
How do you do this question below? :

Calculate the angular displacement in radians of the tip of the minute hand of a clock in one second.

Thanks!
0
10 years ago
#2
Angular speed = Angle / Time
0
#3
But you don't know the angular speed!
0
10 years ago
#4
You use the displacement formula which if my memory serves me right is : A w ?? =??t + 0.5?t²
Ignore this post,read the one after this.
0
#5
I don't know, had my first A2 lesson today, so haven't got that far :/
0
10 years ago
#6
(Original post by abbieisthebest)
But you don't know the angular speed!
It moves around 1/60th of a circle in 60 seconds.
0
10 years ago
#7
(Original post by abbieisthebest)
I don't know, had my first A2 lesson today, so haven't got that far :/
Here is the formula : A sin wt
To get angular velocity,W = 2pi/t =]
0
#8
How did you work that out? Sorry for my ignorance
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#9
Would you be able to show me how you work it out with the example above please?
0
10 years ago
#10
(Original post by abbieisthebest)
Would you be able to show me how you work it out with the example above please?
First find angular velocity which is 2pi/ T,
T= 1/60seconds if I am not wrong.Make sure your calculator is in radians ,the value which you get,plug it into the above formula,cha ching.
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10 years ago
#11
I get pi/1800.
0
10 years ago
#12
(Original post by ibysaiyan)
First find angular velocity which is 2pi/ T,
T= 1/60seconds if I am not wrong.Make sure your calculator is in radians ,the value which you get,plug it into the above formula,cha ching.
It's looking for angular displacement, which should be the distance moved by the hand.

I would:

1) Find out how many degrees a clock goes round in 1 second (360/60)

0
10 years ago
#13
Because it is the minute hand, you do

60 x 60 = 3600

so that is 1/3600 x 2pi

= 1/1800 pi
0
10 years ago
#14
I got pi/1800 using the Angular speed = Angle / Time method and get shot down.
0
5 years ago
#15
First: you have to calculate the degrees of the arc length. 360/60 = 6 degrees

Second: you must convert the degrees into radians. (2pi/360) * 6 = 0.1047... radians

Third: radians * time = 0.1407 * (1/60) = 1.75 * 10^-3 rad s^-1
1
5 years ago
#16
(Original post by abbieisthebest)
How do you do this question below? :

Calculate the angular displacement in radians of the tip of the minute hand of a clock in one second.

Thanks!
Well you know that for every minute the minute hand will rotate 1/60th of the clock. One complete rotation is equal to 2pi. So angular displacement in 1 minute is equal to 2pi/60 rads or pi/30 rads. But it asks for the angular displacement in 1 second, so just simply divide ((pi/30)/60). Final answer should be 1.75x10^-3 rads. I think his is right, anyone tell me if I'm wrong.

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1
5 years ago
#17
Lmao I just realised this was posted 5 years ago. Oh well.

Posted from TSR Mobile
0
3 years ago
#18
(Original post by RossB1702)
Lmao I just realised this was posted 5 years ago. Oh well.

Posted from TSR Mobile
lol, thanks your explanation was the clearest anyway. Students are still struggling with this question 6 years later lol
1
1 year ago
#19
same mate
0
1 year ago
#20
great explanation
0
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