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OCR M1 Question
I can't figure out the last part of q 5 and the whole q 7 in the Jan 05 M1 paper. Can anyone help me to solve this question pls?=)
The first half is relatively easy, but I don't know why i can't solve rest of them..?_?
Q5) Two particles A and B are projected verticaly upwards from horizontal ground at the same instant. The speeds of projection of A and B are 7m/s
and 10.5m/s respectively.
At the instant when B is 3.5m above A, find
iv)whether A is movin upwards or downwards
v) the height of A above the ground
Q7
The upper edge of a smooth plane inclined at 70 degrees to the horizontal is joined to an edge of a rough horizontal table. Particles A and B, of masses 0.3kg and 0.2 kg respectively, are attached to the ends of smooth inclined plane. Particle A is held in contact with the rough horizontal table and particle B is in contact with the smooth inclined plane with the string taut. The coefficient of friction between A and the horizontal table is 0.4. Particle A is released from rest and the system starts to move.
i) Find the acceleration of A and the tension in the string.
The string breaks when the speed of the particles is 1.5m/s
ii) Assuming A does not reach the pulley, find the ditance travelled by a after the string breaks.
iii) Assuming B does not reach the ground before A stops, find the distance travelled by B from the time the string breaks to the time that A stops.
Thzz alot=)
The first half is relatively easy, but I don't know why i can't solve rest of them..?_?
Q5) Two particles A and B are projected verticaly upwards from horizontal ground at the same instant. The speeds of projection of A and B are 7m/s
and 10.5m/s respectively.
At the instant when B is 3.5m above A, find
iv)whether A is movin upwards or downwards
v) the height of A above the ground
Q7
The upper edge of a smooth plane inclined at 70 degrees to the horizontal is joined to an edge of a rough horizontal table. Particles A and B, of masses 0.3kg and 0.2 kg respectively, are attached to the ends of smooth inclined plane. Particle A is held in contact with the rough horizontal table and particle B is in contact with the smooth inclined plane with the string taut. The coefficient of friction between A and the horizontal table is 0.4. Particle A is released from rest and the system starts to move.
i) Find the acceleration of A and the tension in the string.
The string breaks when the speed of the particles is 1.5m/s
ii) Assuming A does not reach the pulley, find the ditance travelled by a after the string breaks.
iii) Assuming B does not reach the ground before A stops, find the distance travelled by B from the time the string breaks to the time that A stops.
Thzz alot=)
Euniceee
Q5) Two particles A and B are projected verticaly upwards from horizontal ground at the same instant. The speeds of projection of A and B are 7m/s
and 10.5m/s respectively.
At the instant when B is 3.5m above A, find
iv)whether A is movin upwards or downwards
v) the height of A above the ground
Q5) Two particles A and B are projected verticaly upwards from horizontal ground at the same instant. The speeds of projection of A and B are 7m/s
and 10.5m/s respectively.
At the instant when B is 3.5m above A, find
iv)whether A is movin upwards or downwards
v) the height of A above the ground
Set up equations for velocity and displacement.
vA = 7 - 9.8t
vB = 10.5-9.8t
SA = 7t - 4.9t²
SB = 10.5t - 4.9t²
B is 3.5m above A, therefore
7t - 4.9t² + 3.5 = 10.5t - 4.9t²
3.5t= 3.5
t= 1 second
So vA = 7-9.8*1
= -2.8
Therefore going downwards
Height of A = SA = 7*1- 4.9*1²
=2.1m
--------------
Euniceee
ii) Assuming A does not reach the pulley, find the ditance travelled by a after the string breaks.
ii) Assuming A does not reach the pulley, find the ditance travelled by a after the string breaks.
There's no pulley mentioned in the question
K, I'll assume you meant a smooth fixed pulley not a smooth plane.
a)
Tension must be constant In the string, so the acceleration must be constant.
forces acting on a = T - 0.08g
on b = 0.8gsin70 - T
2T = 0.3gsin70 + 0.08g
T = 0.15gsin70 + 0.04g = 1.77334 ....
resultant force = 0.3gsin70 - 1.77334 ... = 0.98935
res force = ma res force/mass = a
0.98935/0.3 = a = 3.298 m/s²
that seems like a big acceleration, I'm probably wrong. so I wont go any further lol.
a)
Tension must be constant In the string, so the acceleration must be constant.
forces acting on a = T - 0.08g
on b = 0.8gsin70 - T
2T = 0.3gsin70 + 0.08g
T = 0.15gsin70 + 0.04g = 1.77334 ....
resultant force = 0.3gsin70 - 1.77334 ... = 0.98935
res force = ma res force/mass = a
0.98935/0.3 = a = 3.298 m/s²
that seems like a big acceleration, I'm probably wrong. so I wont go any further lol.
Libertine
Set up equations for velocity and displacement.
vA = 7 - 9.8t
vB = 10.5-9.8t
SA = 7t - 4.9t²
SB = 10.5t - 4.9t²
B is 3.5m above A, therefore
7t - 4.9t² + 3.5 = 10.5t - 4.9t²
3.5t= 3.5
t= 1 second
So vA = 7-9.8*1
= -2.8
Therefore going downwards
Height of A = SA = 7*1- 4.9*1²
=2.1m
--------------
There's no pulley mentioned in the question
vA = 7 - 9.8t
vB = 10.5-9.8t
SA = 7t - 4.9t²
SB = 10.5t - 4.9t²
B is 3.5m above A, therefore
7t - 4.9t² + 3.5 = 10.5t - 4.9t²
3.5t= 3.5
t= 1 second
So vA = 7-9.8*1
= -2.8
Therefore going downwards
Height of A = SA = 7*1- 4.9*1²
=2.1m
--------------
There's no pulley mentioned in the question
Q7
The upper edge of a smooth plane inclined at 70 degrees to the horizontal is joined to an edge of a rough horizontal table. Particles A and B, of masses 0.3kg and 0.2 kg respectively, are attached to the ends of a light inextensible string. The string passes over a smooth pulley which is fixed at the top of the smooth inclined plane. Particle A is held in contact with the rough horizontal table and particle B is in contact with the smooth inclined plane with the string taut. The coefficient of friction between A and the horizontal table is 0.4. Particle A is released from rest and the system starts to move.
i) Find the acceleration of A and the tension in the string.
The string breaks when the speed of the particles is 1.5m/s
ii) Assuming A does not reach the pulley, find the ditance travelled by a after the string breaks.
iii) Assuming B does not reach the ground before A stops, find the distance travelled by B from the time the string breaks to the time that A stops.
thz alot!=)
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