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C2, Any help would be much appreciated!!!!!
Ok, question as follows:
Given that for small values of x
(1+ax)n = 1 - 24x + 270x2
where n is an integer and n>1
a) show that n=16 and find the value of a
b) use your value of a and a suitable value of x to estimate the value of (0.9985)16, giving your answer to 5 decimal places
I keep going round in circles with this, just can't get it. I put it into bionomial expansion, but just ended up getting confused with all the a's and n's and x's! So have given up, and if anyone can enlighten me I would be most grateful!
Given that for small values of x
(1+ax)n = 1 - 24x + 270x2
where n is an integer and n>1
a) show that n=16 and find the value of a
b) use your value of a and a suitable value of x to estimate the value of (0.9985)16, giving your answer to 5 decimal places
I keep going round in circles with this, just can't get it. I put it into bionomial expansion, but just ended up getting confused with all the a's and n's and x's! So have given up, and if anyone can enlighten me I would be most grateful!
Sushmeist
Ok, question as follows:
Given that for small values of x
(1+ax)n = 1 - 24x + 270x2
where n is an integer and n>1
a) show that n=16 and find the value of a
b) use your value of a and a suitable value of x to estimate the value of (0.9985)16, giving your answer to 5 decimal places
I keep going round in circles with this, just can't get it. I put it into bionomial expansion, but just ended up getting confused with all the a's and n's and x's! So have given up, and if anyone can enlighten me I would be most grateful!
Given that for small values of x
(1+ax)n = 1 - 24x + 270x2
where n is an integer and n>1
a) show that n=16 and find the value of a
b) use your value of a and a suitable value of x to estimate the value of (0.9985)16, giving your answer to 5 decimal places
I keep going round in circles with this, just can't get it. I put it into bionomial expansion, but just ended up getting confused with all the a's and n's and x's! So have given up, and if anyone can enlighten me I would be most grateful!
(1+ax)n= 1+ nax + [n(n-1)(ax)²]/2! + [n(n-1)(n-2)(ax)³]/3!+.....
Coefficient of x:
na=-24
Coefficient of x²:
[n(n-1)a²]/2 =270
Two equations, two unknowns ,Can you do it now
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