The Student Room Group
BeitHaller
on Q4 on June 03 S2, does someone mind explaining the thinking behind the answers to the latter 2 parts. Have looked at the mark scheme and still not sure about it.
Not the normal kind of S2 question i'm used to.
ta


Why don't you post the actual question up (all of it), so we can actually see it?
Reply 2
A six sided die is biased. When the die is thrown the number 5 is twice as likely to appear as any other number. All the other faces are equaly likely to appear. The die is thrown repeatedly.

Find the probability that
b) i ) the first 5 will occur on the sixth throw

Answer:
Probability for a five is 2/7
Probability for any other number will theoretically be 5/7
(because die is biased.... the probability for any other number will be 1/7)

The first five occuring on sixth throw =
(5/7)^5 . (2/7)
= 0.05312.....

ii) First eight throws there will be exactly 3 fives

same probabilities as above
(8C3) . (2/7)^3 . (5/7)^5
= 0.24285.....
Reply 3
ah that makes more sense. The mark scheme's working (was the one from the link given in another thread) was completely wrong, despite the answers given being correct. thanks