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# 3D Pythagoras watch

1. Does anyone know how to do 3D pythagoras which i can apparently include in my GCSE Maths coursework to get an A*. The coursework is called Beyond Pythagoras.

2. Imagine the point A = (x,y,z), Now we want to find the distance OA?

Now draw a line from A to meet the plane, perpendicularly, at M.

Therefore what is |OM| using pythagoras? What is |MA|? So what is |OA|?
3. (Original post by theone)
Imagine the point A = (x,y,z), Now we want to find the distance OA?

Now draw a line from A to meet the plane, perpendicularly, at M.

Therefore what is |OM| using pythagoras? What is |MA|? So what is |OA|?
Why are you using modulus? Its GCSE...
4. (Original post by bono)
Why are you using modulus? Its GCSE...
I think he is using it as vector notation.
5. (Original post by capslock)
I think he is using it as vector notation.
Yes, in vector notation, |OA| means the distance from O to A as opposed to OA which could mean the distance or the vector from O to A.
6. a man travels one mile north, one mile east, and one mile upwards, then directly home again.
try working out his total distance travelled.

you don't need any extra laws, just pythagoras.
7. (Original post by bono)
Why are you using modulus? Its GCSE...
whats wrong with using mod in gcse?
8. (Original post by mik1a)
a man travels one mile north, one mile east, and one mile upwards, then directly home again.
try working out his total distance travelled.

you don't need any extra laws, just pythagoras.
1 + 1 + 1 + root of (root of 2 + 1)
9. (Original post by mik1a)
a man travels one mile north, one mile east, and one mile upwards, then directly home again.
try working out his total distance travelled.

you don't need any extra laws, just pythagoras.
3+sqrt(3)
10. (Original post by ZJuwelH)
3+sqrt(3)
Or could it be 4+sqrt(2)...

Sod it, I got it right in the Maths Challenge, I'm knackered...
11. lol i thought someone would pick up on that
i stole the question from smc
12. (Original post by ZJuwelH)
Or could it be 4+sqrt(2)...

Sod it, I got it right in the Maths Challenge, I'm knackered...

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Updated: February 12, 2004
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