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    answers
    a)0.3ms^-1
    b)-0.1ms^-1
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    And what have you tried so far?
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    (Original post by Phenomenological)
    And what have you tried so far?
    All sorts of random things lol, but for one I know it's final velocity-initial velocity/time, so it would be 4/40=0.1ms^-1 but I don't really understand the difference between speed and velocity so I'm not sure which one that applies to and why...
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    (Original post by BuuTuu)
    http://s1116.photobucket.com/albums/...t=DSC_0002.jpg


    answers
    a)0.3ms^-1
    b)-0.1ms^-1
    a) From the graph, you can see that the lift goes up 4m, then down 8m. So average speed = distance/time = 12/40.

    b) The displacement is the distance traveled in a given direction, in this case, 4m down. Velocity = Displacement/time.
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    (Original post by BuuTuu)
    I don't really understand the difference between speed and velocity so I'm not sure which one that applies to and why...
    Speed = distance covered per second in any direction
    Velocity = distance covered per second in a particular direction

    For example, if you run forwards 5 metres and then back 5 metres in two seconds, your average speed is 5 metres per second. But your average velocity is 0 because you are back where you started.
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    (Original post by BuuTuu)
    http://s1116.photobucket.com/albums/...t=DSC_0002.jpg


    answers
    a)0.3ms^-1
    b)-0.1ms^-1
    a) The question asks for the average speed so you need to do S = D/t
    The graph shows displacement which is a vector quantity, Distance is a scalar.
    Overall displacement is -4m but the distance covered is 12m so 12/4 =0.3ms^-1

    b) This asks for the average velocity (which is a vector quantity) so you need to calculate Δs/t so -4/40 =0.1ms^-1

    Hope this helps?
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    Velocity is a vector. Speed is a scalar.
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    (Original post by tom28)
    a) From the graph, you can see that the lift goes up 4m, then down 8m. So average speed = distance/time = 12/40.

    b) The displacement is the distance traveled in a given direction, in this case, 4m down. Velocity = Displacement/time.
    thank you v.much
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    (Original post by Phenomenological)
    Speed = distance covered per second in any direction
    Velocity = distance covered per second in a particular direction

    For example, if you run forwards 5 metres and then back 5 metres in two seconds, your average speed is 5 metres per second. But your average velocity is 0 because you are back where you started.
    ohhh, ok I get it now thank you
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    (Original post by no1_titch)
    a) The question asks for the average speed so you need to do S = D/t
    The graph shows displacement which is a vector quantity, Distance is a scalar.
    Overall displacement is -4m but the distance covered is 12m so 12/4 =0.3ms^-1

    b) This asks for the average velocity (which is a vector quantity) so you need to calculate Δs/t so -4/40 =0.1ms^-1

    Hope this helps?
    It does thank you
 
 
 
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