I'm assuming the pressure is directly proportional to the distance (d) from the surface?
a)Just say at 3m, pressure = 200
divide both sides by 3 , for 1m change in depth = 200/3 change in pressure
so 5m = (200/3)x5 = 1000/3 , about 333.33
b) 4000 at 20m/s
1m/s = 4000/20 = 200
for every 1m/s change in velocity there is a 200N change in resistive force.
at 30m/s :
force at 1 m/s x 30 = 200x30 = 6000N.
Any good?
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For every 1N change in resistance there is a velocity change associated with it of value:
1N = 20/4000 = 2/400 = 1/200
so at 6250 N , the velocity associated with it is , (1/200) x 6250 = 6250/200 = 31.25 m/s.