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    1. Simplify √24 +√6. I got 5√12...is this correct?

    2. Express (fraction) 36 which is over 5-√7 in the form a+b√7, where a and b are integers. I got 10+2√7...is this correct?

    3. Make X the subject of this formula: (its a fraction) 'a', over (x-b)^2=c (the whole fraction equals C, not the (x-b)^2)

    ^^ I cant seem to get a reasonable looking answer for no.3.
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    1. No, the answer is in terms of √6 only, just simplify the √24 into √6's.

    2. Yes it is

    3. What answer did you get?
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    simple?
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    (Original post by CJN)
    1. No, the answer is in terms of √6 only, just simplify the √24 into √6's.

    3. What answer did you get?
    I got a^2+b (all over) c^2 =x (whole fraction equalling x not the c^2)
    Right or not? If not whats the right answer?

    And is the answer to Q1. 4√6?

    Thanks.
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    √24 + √6 is not 4√6
    √24 => √4√6 => 2√6

    2√6 + √6, which is 3√6 not 4
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    I got 3√6 for Q1

    √24 broken down to √6*√4, so that's 2√6.

    2√6 + √6 = 3√6

    My maths is a bit rusty so I don't exclude being completely wrong
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    (Original post by Saif95)
    I got a^2+b (all over) c^2 =x (whole fraction equalling x not the c^2)
    Right or not? If not whats the right answer?

    And is the answer to Q1. 4√6?

    Thanks.
    What is root 24 in terms of root 6?
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    (Original post by Nucleo)
    √24 + √6 is not 4√6
    √24 => √4√6 => 2√6

    2√6 + √6, which is 3√6 not 4
    (Original post by ryan84)
    What is root 24 in terms of root 6?
    Yh thanks I get it now...

    can you tell me if my answer to the 3rd question was right? if not what is it?
    thanks.
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    (Original post by Saif95)
    Yh thanks I get it now...

    can you tell me if my answer to the 3rd question was right? if not what is it?
    thanks.
    Not sure what you are doing, but:

     \dfrac{a}{(x-b)^2} = c


     c \times (x - b)^2 = a


     (x - b)^2 = \dfrac{a}{c}


     x - b = \sqrt{\dfrac{a}{c}}


     x = \sqrt{\dfrac{a}{c}} + b
 
 
 
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