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Reply 1

Original post
by Erotas
How to integrate sec^2xtan^2x.

I've tried it by parts but that doesn't seem to work.

Any help/hints much appreciated.


what is the derivative of tan(x)?

try a substitution u = tan(x)

with a bit of thought you can answer this mentally.

Reply 2

Sec and Tan have a very close relationship, in terms of trig identities. See if you can get it in terms of only tan or sec (or powers of) and see if that is easier to integrate.

Reply 3

Original post
by FireGarden
Sec and Tan have a very close relationship, in terms of trig identities. See if you can get it in terms of only tan or sec (or powers of) and see if that is easier to integrate.


that won't work.

Reply 4

Original post
by Erotas
How to integrate sec^2xtan^2x.

I've tried it by parts but that doesn't seem to work.

Any help/hints much appreciated.


Keep breaking it down until you find something you can work with:

Let u=sec^2 and v=tan^2
and if that's still too much at this stage:

Let a=sec b=sec c=tan d=tan
Differentiate a and b, use the product rule to find u; differentiate c and d, use the product rule to find v. Then just use the product rule on u and v.

Reply 5

Original post
by Cupid93
Keep breaking it down until you find something you can work with:

Let u=sec^2 and v=tan^2
and if that's still too much at this stage:

Let a=sec b=sec c=tan d=tan
Differentiate a and b, use the product rule to find u; differentiate c and d, use the product rule to find v. Then just use the product rule on u and v.


The question is on integration. the product rule has nothing to do with it.

the "method" is given in my first post.

Reply 6

Use the formula \displaystyle\int f^n(x) f^{'}(x)\ dx = \dfrac{f^{n+1}(x)}{n+1} to get \dfrac{\tan^{3} x}{3} + k. Do you know how to do that?

Reply 7

Original post
by H.C. Chinaski
The question is on integration. the product rule has nothing to do with it.

the "method" is given in my first post.


I think u = tan^2x is a better substitution

Reply 8

Original post
by H.C. Chinaski
what is the derivative of tan(x)?

try a substitution u = tan(x)

with a bit of thought you can answer this mentally.


yup.

using substitution, u=tan (x) and du= sec^2 (x) dx

U can integrate normally from there and substitute tan(x) back in,
you'll get (1/3)tan^3 (x) + c

Reply 9

You are asked to evaluate:

\displaystyle\int \sec^2 x\tan^2 x\ dx

Let u = \tan x

\implies du = \sec^2 x\ dx

Carry out this substitution and evaluate the resulting integral.

Reply 10

Original post
by Femto
You are asked to evaluate:

\displaystyle\int \sec^2 x\tan^2 x\ dx

Let u = \tan x

\implies du = \sec^2 x\ dx

Carry out this substitution and evaluate the resulting integral.


This is the one, beat me to the post.

Reply 11

Original post
by Danf159
yup.

using substitution, u=tan (x) and du= sec^2 (x) dx

U can integrate normally from there and substitute tan(x) back in,
you'll get (1/3)tan^3 (x) + c


indeed.

op

look out for situations where you are integrating f'(x)g(f(x))

all such cases can be solved with the substitution u=f(x)

(they can also be done by considering Integral g(f(x)) df(x))

Reply 12

Original post
by steve2005
I think u = tan^2x is a better substitution


how is that better????

with u=tan(x) you can see that the answer is (tan(x))^3 / 3 +c without any more thought????

with your approach you get u' = 2 tan(x) sec^2 (x) and I am afraid that this does not lead to an easier approach.

Reply 13

isn't this simply a reverse chain rule....

Reply 14

Original post
by Zishi
Use the formula \displaystyle\int f^n(x) f^{'}(x)\ dx = \dfrac{f^{n+1}(x)}{n+1} to get \dfrac{tan^{3} x}{3} + k. Do you know how to do that?


i think people ignore ur simple reverse chain rule lol ( y )

Reply 15

Original post
by Average
isn't this simply a reverse chain rule....


yes

Reply 16

The easiest way to integrate tanx power n is to have sec^2x as it is the differentiation of tanx... All u need to know is chain rule.

Reply 17

Original post
by Average
i think people ignore ur simple reverse chain rule lol ( y )


I don't think that it is a case of ignoring rules as such, but rather that learning sets of rules that only work in specific cases is a methods approach rather than a mathematical approach and does not appeal to some people here. A-level text books are increasingly guilty of dumbing down understanding and replacing it with rote methods of the type:

If you see A then the answer is B
If you see C then the answer is D
If you see ....etc ....

A more fundamental approach encourages understanding and independence.
(edited 14 years ago)

Reply 18

Thanks for all your help guys!

I tried it first using u = tan^2x like steve2005 said which worked.
I also tried it using u = tanx which worked out to be tan^3x/3 really easily too. Much simpler than I thought.

Reply 19

Original post
by H.C. Chinaski
I don't think that it is a case of ignoring rules as such, but rather that learning sets of rules that only work in specific cases is a methods approach rather than a mathematical approach and does not appeal to some people here. A-level text books are increasingly guilty of dumbing down understanding and replacing it with rote methods of the type:

If you see A then the answer is B
If you see C then the answer is D
If you see ....etc ....

A more fundamental approach encourages understanding and independence.


right... I hate rules too. However, integration is not mathematical. Unlike other concepts, integration is formed based on reversing differentiation. You would understand if you think about it thoroughly. Moreover, i think a level basics help with further understanding.