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    I'm unsure what  \frac{2}{x} would look like. I know  \frac{1}{x-a} is the translation by (-a, 0) and  \frac{1}{x} + a is the translation by (0, a), but would that mean  \frac{a}{x} is the same as af(x) (stretching of the SF a in the y direction)? If someone could show me how I could stretch this curve (or what it looks like) it'd be much appreciated
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    type it into wolfram alpha together with \frac{1}{x} and \frac{3}{x} the pattern will become clear
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    (Original post by TenOfThem)
    type it into wolfram alpha together with \frac{1}{x} and \frac{3}{x} the pattern will become clear
    The curve looks like the same...it's only the axes that changes? :/
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    Have you typed them into he same set of axes so that you can compare them
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    (Original post by TenOfThem)
    Have you typed them into he same set of axes so that you can compare them
    Oh right. Well 2/x is a lil further away from the x and y axis... is that right?
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    less steep as well
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    (Original post by TenOfThem)
    less steep as well
    cool, thanks
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    (Original post by InadequateJusticex)
    Oh right. Well 2/x is a lil further away from the x and y axis... is that right?
    Exactly, the larger the number on top, the further away from both axes.
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    (Original post by JOR2010)
    Exactly, the larger the number on top, the further away from both axes.
    Until infinity
 
 
 
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