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Urgent!!!! need help!!! watch

1. I have my final exam tommorow which is 30% of the grade and I can't solve these sample questions. I need help!!!! Thanks.
3. argh..............
4. which exam is that? All of them ??? and you need help at this time ??
Ok, I'll try the 1st
5. thank you so much!!! i have my high school math exam tommorow!!! and it's only 9pm cuz its canada
6. Do you know about the meeting point of median lines in a triangle ???

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My suggestion is:
You take X' is the midpoint of CD, then you prove that AX' cuts BD at O' which statisfies: BO' = O'D.

-> O' = O => X' = X.

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I need to go to sleep btw It's very very late here. Sorry
7. i have to use vector method.... there is going to be number of vector proof question on the exam
8. (Original post by jeongsuman)
i have to use vector method.... there is going to be number of vector proof question on the exam
Ah, ok, then let a = AB, b = AD
I am sure you can find the expression of AO in term of a and b

Then you may find CX and DX in tems of a and b
You'll see CX = XD
9. how????? -_-
10. (Original post by jeongsuman)
how????? -_-
It seems too late now. Yesterday, I had to go to bed, that time was 3am already, and I had lecture at 9am. Sorry.

Let AB = a, AD = b

=>AC = a + b

So AO = 1/3 a + 2/3b

Let |DX|/|DC| = k

=> 1-k = |XC|/|DC|

So AX = kAC + (1-k)AD = k(a +b) + (1-k)b

=> AX = ka + b

Since AX has the same direction with AO

Then compare the coefficients of a and b we have
k÷(1/3) = 1÷(2/3)
Then you'll get k = 1/2

So DX = XC = 1/2DC
11. the same question appeared on the exam and i couldn't solve it... anyway thanks for solving the question
12. So did you do well with other questions??
13. yes other questions were pretty straightforward

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