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Eliminating parameter to find cartesian equation watch

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    I'm trying to eliminate the paramter to find a cartesian equation. The problem given is

    x=cosh t
    y=sinh t

    The answer sections gives x2-y2=cosh2t-sinh2t. Then it says t=1. How did it get to t=1? I understand the first part, both sides were squared. Many thanks
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    x = cosht, y = sinht
    x^2 - y^2 = cosh^2(t) - sinh^2(t) = 1

    And that's your cartesian equation.
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    http://www.sosmath.com/trig/hyper/hyper01/img5.gif
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    Is that something I'm just supposed to know? I've never seen that in my life before. I know sin2+cos2=1.
 
 
 
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Updated: January 31, 2006

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