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Solve the equation 4x2 + 12x = 0.
(factorise)
4x(x+3)=0
x=0
x=-3


f(x) = 4x2 + 12x + c,
Given that f(x) = 0 has equal roots, find the value of c and hence solve f(x) = 0.

b^2 -4ac=0 (since it has 2 roots)
12^2-(4x4xc)=0
144-16c=0
c= -144/-16


The points A and B have coordinates (1, 2) and (5, 8) respectively.
(a)Find the coordinates of the mid-point of AB.

(1+5)/2, (2+8)/2
= (3,5)

(b)Find, in the form y = mx +c, an equation for the straight line through A and B.

y=mx+c
5=mx3+c

find m:
m= (8-2)/ (5-1)
m= 6/4 = 3/2

so: 5= 3/2 x 3+ c

(then you can find the c)

i did this in a hurry, i hope it's right (the methods anyway) :smile:
Reply 2
Fenchurch
Help with these plz!

Solve the equation 4x2 + 12x = 0.


f(x) = 4x2 + 12x + c,

where c is a constant.

Given that f(x) = 0 has equal roots, find the value of c and hence solve f(x) = 0.
if it has equal roots then b^2-4ac=0

so a=4 b=12 c=c
144-16c=0
144=16c
c=9
4x2 + 12x + 9


And


The points A and B have coordinates (1, 2) and (5, 8) respectively.

(a)Find the coordinates of the mid-point of AB.
(
(b)Find, in the form y = mx +c, an equation for the straight line through A and B.
mid points is x1+x2 divided by and the same for y so
(1+5)/2 = 3, (2+8)/2 = 5 so mid point is (3,5)

B) gradient = (y2-y1)/(x2-X1) so (8-2)/(5-1) =6/4 = 3/2 which is 1.5

so because its passes through A and B you can use either co-ordinates

y-2=3/2(x-1) so y=3/2x-3/2+2
y=3/2x+1/2