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# arcsin(cosx) watch

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1. h(x) = arcsin(cos x) where 0<x<pi

dh/dx = -1

"what can you deduce about h(x) for x is this range?"

what is there to deduce?!

for x is between 0 and pi, cosx ranges from 1 to -1
then arcsin of 1 and -1 is pi/2 and -pi/2

um......i really don't know what i am meant to do. please could u help
2. (Original post by davemarkey)
h(x) = arcsin(cos x) where 0<x<pi

dh/dx = -1

"what can you deduce about h(x) for x is this range?"

what is there to deduce?!

for x is between 0 and pi, cosx ranges from 1 to -1
then arcsin of 1 and -1 is pi/2 and -pi/2

um......i really don't know what i am meant to do. please could u help
Negative dy/dx => arcsin(cosx) is a decreasing function in the range 0<x<pi
3. (Original post by Widowmaker)
Negative dy/dx => arcsin(cosx) is a decreasing function in the range 0<x<pi
oh, thats all

thanks
4. You could deduce it's constant - x.

constant = pi/2 in fact

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