arcsin(cosx)

h(x) = arcsin(cos x) where 0<x<pi

dh/dx = -1

"what can you deduce about h(x) for x is this range?"

:confused:

what is there to deduce?!

for x is between 0 and pi, cosx ranges from 1 to -1
then arcsin of 1 and -1 is pi/2 and -pi/2

:confused:

um......i really don't know what i am meant to do. please could u help :redface:

Reply 1

davemarkey

h(x) = arcsin(cos x) where 0<x<pi

dh/dx = -1

"what can you deduce about h(x) for x is this range?"

:confused:

what is there to deduce?!

for x is between 0 and pi, cosx ranges from 1 to -1
then arcsin of 1 and -1 is pi/2 and -pi/2

:confused:

um......i really don't know what i am meant to do. please could u help :redface:

Negative dy/dx => arcsin(cosx) is a decreasing function in the range 0<x<pi

Reply 2

Widowmaker

Negative dy/dx => arcsin(cosx) is a decreasing function in the range 0<x<pi

oh, thats all :redface:

thanks

Reply 3

You could deduce it's constant - x.

constant = pi/2 in fact

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