There is an answer which shows "R= Cube Root of (6V/PI) / 2" in an assessment book. Does anyone know how the author went to this final answer instead of what was given by James H. above?
There is an answer which shows "R= Cube Root of (6V/PI) / 2" in an assessment book. Does anyone know how the author went to this final answer instead of what was given by James H. above?
Any idea?
3V/4 = 6V/8 so they've just taken the cube root of 8 (i.e. 2) outside the root sign