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    A transport plane is towing a glider, which in turn is towing a second glider. They accelerate from rest on a level runway. The plane and gliders remain in a straight line and the tow ropes are horizontal. The gliders each have a mass of 1000 kg. Assume the force opposing the motion of each glider is constant at 1500 N. The plane reaches a speed of 40m/s after accelerating uniformly over a distance of 320 m.

    Find acceleration of the plane.

    During the acceleration, calculate: the tension in the tow rope between the two gliders, and the tension in the tow rope between the plane and the first glider.

    I got the first answer: 2.5m/s^2. What else?
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    I was about to answer the question but theres no way of hinting without labelling the forces (which is the question)

    all you need is F=ma and to assume that the two ropes are inextensible- therefore meaning every part of the system has the same acceleration.

    draw a force diagram and you've done the question...
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    (Original post by hai2410)
    I was about to answer the question but theres no way of hinting without labelling the forces (which is the question)

    all you need is F=ma and to assume that the two ropes are inextensible- therefore meaning every part of the system has the same acceleration.

    draw a force diagram and you've done the question...
    2500+1500=4000 for first one
    4000*2=8000 for second one

    Are the steps correct?
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    (Original post by bbrain)
    2500+1500=4000 for first one
    4000*2=8000 for second one

    Are the steps correct?
    I agree with your answers, yes.

    If your method was to write out the equations of motion for each glider and solve, I agree with your steps.
 
 
 
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