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    Can someone please help me with this question

    2) The equation of the line L is 2x+3y=24 and A is the point (4,1)

    a) find the gradient of the line L

    b) hence write down the gradient of a line perpendicular to L
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    To find the gradient of L re-arrange the equation and divide by 3. Then the gradient= co-efficient of the x.

    The gradient of the line perpendicular to L= -1/(gradient of L).
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    rearrange to get y=
    then you will have the gradient

    hopefully you know the rule connecting the gradients of perpendicular lines
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    I won't give you the answer, but it's pretty simple.

    To get the gradient:

    Rearrange 2x+3y=24 in the form of y=mx+c

    'm' is the gradient.

    When a line is perpendicular - m1 x m2 = -1

    So just pop your gradient into that line to find the gradient of the other line.

    To work out the equation of a line use - y-y1=m(x-x1)

    Substitute the x and y coordinates from the point (4,1) into the equation with your new gradient to get the answer to b.
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    (Original post by AspiringGenius)
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    Giving the answers isn't help! :rolleyes:
 
 
 

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